Homework 13 Quadratic Equation Word Problems

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Mar 04, 2025 · 6 min read

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Homework 13: Quadratic Equation Word Problems – A Comprehensive Guide
Homework assignments focused on quadratic equation word problems can be daunting, but mastering them is crucial for success in algebra and beyond. These problems require not only a solid understanding of quadratic equations but also the ability to translate real-world scenarios into mathematical models. This comprehensive guide will walk you through various types of quadratic word problems, providing step-by-step solutions and strategies to tackle them effectively. We’ll cover everything from projectile motion to geometry problems, ensuring you’re well-equipped to conquer your homework and beyond.
Understanding Quadratic Equations
Before diving into word problems, let's refresh our understanding of quadratic equations. A quadratic equation is an equation of the form:
ax² + bx + c = 0
where 'a', 'b', and 'c' are constants, and 'a' is not equal to zero. Solving these equations involves finding the values of 'x' that satisfy the equation. Common methods for solving include:
- Factoring: This involves rewriting the equation as a product of two binomials.
- Quadratic Formula: This formula provides a direct solution for 'x': x = [-b ± √(b² - 4ac)] / 2a
- Completing the Square: This method involves manipulating the equation to create a perfect square trinomial.
Mastering these methods is fundamental to solving quadratic word problems.
Types of Quadratic Word Problems and Strategies for Solving Them
Quadratic word problems appear in various contexts. Here are some common types and strategies for approaching them:
1. Area Problems
Many problems involve calculating the area of a rectangle, square, or other geometric shapes. The area often provides the quadratic equation.
Example: A rectangular garden is 3 feet longer than it is wide. If the area of the garden is 70 square feet, what are its dimensions?
Solution:
- Define variables: Let 'w' represent the width. The length is then 'w + 3'.
- Set up the equation: The area is width × length, so we have w(w + 3) = 70.
- Expand and rearrange: w² + 3w - 70 = 0
- Solve the equation: This quadratic can be factored as (w + 10)(w - 7) = 0. The solutions are w = -10 and w = 7. Since width cannot be negative, the width is 7 feet.
- Find the length: The length is w + 3 = 7 + 3 = 10 feet.
- Answer: The garden is 7 feet wide and 10 feet long.
2. Projectile Motion Problems
These problems involve objects thrown or launched into the air, often under the influence of gravity. The height of the object as a function of time is typically a quadratic equation.
Example: A ball is thrown upward from the ground with an initial velocity of 64 feet per second. Its height (h) after t seconds is given by the equation h(t) = -16t² + 64t. When does the ball reach its maximum height, and what is that height?
Solution:
- Understanding the Equation: The equation h(t) = -16t² + 64t represents a parabola. The maximum height occurs at the vertex of the parabola.
- Finding the Vertex: The x-coordinate (t-coordinate in this case) of the vertex of a parabola given by ax² + bx + c is -b/2a. In our equation, a = -16 and b = 64. Therefore, the time at which the maximum height is reached is t = -64 / (2 * -16) = 2 seconds.
- Finding the Maximum Height: Substitute t = 2 into the equation: h(2) = -16(2)² + 64(2) = 64 feet.
- Answer: The ball reaches its maximum height of 64 feet after 2 seconds.
3. Number Problems
Some problems involve finding two numbers based on their relationship and the result of a specific operation.
Example: The product of two consecutive odd integers is 99. Find the integers.
Solution:
- Define variables: Let 'x' be the first odd integer. The next consecutive odd integer is 'x + 2'.
- Set up the equation: Their product is 99, so x(x + 2) = 99.
- Expand and rearrange: x² + 2x - 99 = 0
- Solve the equation: This quadratic can be factored as (x + 11)(x - 9) = 0. The solutions are x = -11 and x = 9.
- Find the integers: If x = 9, the integers are 9 and 11. If x = -11, the integers are -11 and -9.
- Answer: The two pairs of consecutive odd integers are 9 and 11, and -11 and -9.
4. Geometry Problems (Beyond Area)
Quadratic equations can also arise in problems involving other geometric properties, such as the Pythagorean theorem.
Example: A right-angled triangle has a hypotenuse of 13 cm. One leg is 7 cm longer than the other. Find the lengths of the legs.
Solution:
- Define variables: Let x be the length of the shorter leg. The longer leg is x + 7.
- Apply the Pythagorean theorem: x² + (x + 7)² = 13²
- Expand and simplify: x² + x² + 14x + 49 = 169 => 2x² + 14x - 120 = 0
- Solve the equation: Divide by 2: x² + 7x - 60 = 0. This factors to (x + 12)(x - 5) = 0. The solutions are x = -12 and x = 5. Since length cannot be negative, x = 5.
- Find the leg lengths: The shorter leg is 5 cm, and the longer leg is 5 + 7 = 12 cm.
- Answer: The legs of the triangle are 5 cm and 12 cm.
Advanced Strategies and Considerations
- Visual Representations: Drawing diagrams for geometry problems can significantly aid in understanding the problem and setting up the equation.
- Checking Solutions: Always check your solutions in the original word problem to ensure they make sense in the context of the problem. Negative solutions might be extraneous depending on the context (e.g., length, time).
- Units: Pay close attention to units (feet, meters, seconds, etc.) and ensure consistency throughout your calculations.
- Real-World Application: Understanding the real-world implications of the problem can help in interpreting the solutions and determining if they are reasonable.
Practice Makes Perfect
The key to mastering quadratic equation word problems is consistent practice. Work through a variety of problems, focusing on understanding the underlying concepts and applying the appropriate solution methods. Start with simpler problems and gradually progress to more complex scenarios. Don't hesitate to seek help from teachers, tutors, or online resources if you encounter difficulties.
Conclusion
Solving quadratic equation word problems is a valuable skill that bridges the gap between abstract mathematical concepts and real-world applications. By understanding the different types of problems, mastering the solution methods, and practicing regularly, you can build confidence and achieve success in this important area of algebra. Remember to break down each problem step-by-step, define your variables clearly, and always check your answers for reasonableness and accuracy. With consistent effort and a systematic approach, you'll be well on your way to mastering these challenging yet rewarding problems. Good luck with your Homework 13!
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