Topic 2.8 Inverse Functions Answer Key

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Mar 27, 2025 · 4 min read

Topic 2.8 Inverse Functions Answer Key
Topic 2.8 Inverse Functions Answer Key

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    Topic 2.8: Inverse Functions – A Comprehensive Guide with Answer Key

    Understanding inverse functions is crucial for mastering algebra and precalculus. This comprehensive guide will delve into the concept of inverse functions, providing a detailed explanation, examples, and a complete answer key for practice problems. We'll explore how to find inverse functions, verify them, and understand their graphical representation. Let's dive in!

    What are Inverse Functions?

    An inverse function essentially "undoes" what the original function does. If a function f maps an input x to an output y, its inverse function, denoted as f<sup>-1</sup>(x) (read as "f inverse of x"), maps that output y back to the original input x. This is only possible if the original function is one-to-one (also known as injective), meaning each input has a unique output, and vice versa. If a function is not one-to-one, you can sometimes restrict its domain to create a one-to-one function that allows for an inverse.

    Key Characteristic: The composition of a function and its inverse results in the identity function, meaning f(f<sup>-1</sup>(x)) = x and f<sup>-1</sup>(f(x)) = x.

    How to Find the Inverse of a Function

    Finding the inverse of a function involves a systematic process:

    1. Replace f(x) with y: This simplifies the notation.

    2. Swap x and y: This is the crucial step that reverses the mapping.

    3. Solve for y: Algebraically manipulate the equation to isolate y.

    4. Replace y with f<sup>-1</sup>(x): This denotes the inverse function.

    Example 1: Find the inverse of f(x) = 2x + 3.

    1. y = 2x + 3
    2. x = 2y + 3
    3. x - 3 = 2y
    4. y = (x - 3) / 2
    5. Therefore, f<sup>-1</sup>(x) = (x - 3) / 2

    Example 2: Find the inverse of f(x) = x² (for x ≥ 0). Notice the restriction on the domain. Without it, the function wouldn't be one-to-one.

    1. y = x²
    2. x = y²
    3. y = ±√x
    4. Since x ≥ 0, we only consider the positive square root.
    5. Therefore, f<sup>-1</sup>(x) = √x

    Verifying Inverse Functions

    After finding the inverse, it's essential to verify your result. This is done by checking if the compositions f(f<sup>-1</sup>(x)) = x and f<sup>-1</sup>(f(x)) = x hold true.

    Example 3: Verify the inverse found in Example 1.

    f(f<sup>-1</sup>(x)) = f((x - 3) / 2) = 2((x - 3) / 2) + 3 = x - 3 + 3 = x

    f<sup>-1</sup>(f(x)) = f<sup>-1</sup>(2x + 3) = ((2x + 3) - 3) / 2 = 2x / 2 = x

    Since both compositions result in x, the inverse function is correctly found.

    Graphical Representation of Inverse Functions

    The graphs of a function and its inverse are reflections of each other across the line y = x. This is because swapping x and y in the equation corresponds to a reflection about the line y = x.

    Common Mistakes to Avoid

    • Forgetting to swap x and y: This is the most frequent error. Remember, this step is the core of finding the inverse.

    • Incorrect algebraic manipulation: Carefully solve for y to avoid errors. Check your steps.

    • Ignoring domain restrictions: If the original function isn't one-to-one, restrict its domain to make it so before finding the inverse.

    • Not verifying the inverse: Always verify your solution to ensure accuracy.

    Practice Problems with Answer Key

    Now, let's test your understanding with some practice problems. Remember to follow the steps outlined above.

    Problem 1: Find the inverse of f(x) = 5x - 7.

    Problem 2: Find the inverse of f(x) = (x + 2) / 3.

    Problem 3: Find the inverse of f(x) = x³ + 1.

    Problem 4: Find the inverse of f(x) = √(x - 4) (for x ≥ 4).

    Problem 5: Find the inverse of f(x) = 1/x (for x ≠ 0).

    Problem 6: Find the inverse of f(x) = 2<sup>x</sup>. (Hint: Consider logarithmic functions)

    Problem 7: Verify your answer for Problem 1.

    Problem 8: Verify your answer for Problem 4.

    Answer Key

    Problem 1: f<sup>-1</sup>(x) = (x + 7) / 5

    Problem 2: f<sup>-1</sup>(x) = 3x - 2

    Problem 3: f<sup>-1</sup>(x) = ∛(x - 1)

    Problem 4: f<sup>-1</sup>(x) = x² + 4 (for x ≥ 0)

    Problem 5: f<sup>-1</sup>(x) = 1/x (for x ≠ 0) (Notice that the inverse is the same as the original function!)

    Problem 6: f<sup>-1</sup>(x) = log₂(x) (for x > 0)

    Problem 7: Verification: f(f<sup>-1</sup>(x)) = 5((x + 7) / 5) - 7 = x + 7 - 7 = x f<sup>-1</sup>(f(x)) = ((5x - 7) + 7) / 5 = 5x / 5 = x

    Problem 8: Verification: f(f<sup>-1</sup>(x)) = √((x² + 4) - 4) = √(x²) = x (for x ≥ 0) f<sup>-1</sup>(f(x)) = (√(x - 4))² + 4 = x - 4 + 4 = x (for x ≥ 4)

    Conclusion

    Mastering inverse functions is a cornerstone of advanced mathematical concepts. By understanding the process, verifying your results, and practicing regularly, you'll build a strong foundation for future studies in calculus and beyond. Remember to always check your work and pay attention to domain restrictions. Practice these problems diligently, and refer back to this guide as needed. Good luck!

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